leetcode268缺失数字

int missingNumber(int* nums, int numsSize) {

int sum = numsSize*(numsSize+1) /2;
    
    for(int i=0;i<numsSize;i++){
        sum = sum - nums[i];
    }
return sum; 
}

 

转载于:https://www.cnblogs.com/zhuxuan1997/p/10691959.html