SPOJ 375 Query on a tree（树链剖分）（QTREE）

You are given a tree (an acyclic undirected connected graph) with N nodes, and edges numbered 1, 2, 3...N-1.

We will ask you to perfrom some instructions of the following form:

• CHANGE i ti : change the cost of the i-th edge to ti
  or
• QUERY a b : ask for the maximum edge cost on the path from node a to node b

Input

The first line of input contains an integer t, the number of test cases (t <= 20). t test cases follow.

For each test case:

• In the first line there is an integer N (N <= 10000),
• In the next N-1 lines, the i-th line describes the i-th edge: a line with three integers a b c denotes an edge between a, b of cost c (c <= 1000000),
• The next lines contain instructions "CHANGE i ti" or "QUERY a b",
• The end of each test case is signified by the string "DONE".

There is one blank line between successive tests.

Output

For each "QUERY" operation, write one integer representing its result.

Example

Input:
1

3
1 2 1
2 3 2
QUERY 1 2
CHANGE 1 3
QUERY 1 2
DONE

Output:
1
3

 

推荐论文：《树链剖分》：http://wenku.baidu.com/view/a088de01eff9aef8941e06c3.html

《QTREE解法的一些研究》：随便百度一下就有

 

思路：树链剖分，上面都讲得比较清楚了我就不讲了。对着树链剖分的伪代码写的，那个伪代码有一个错误（应该是错误吧……），询问那里应该是x = father[top[x]]。还有，在这题用线段树，点的权值记录与父节点的边的权值，那么最后的询问是要query(tid[x]+1, tid[y])

代码（3840MS）：

  1 #include <cstdio>
  2 #include <iostream>
  3 #include <algorithm>
  4 #include <cstring>
  5 using namespace std;
  6 
  7 const int MAXN = 10010;
  8 const int MAXE = 2 * MAXN;
  9 const int INF = 0x7fffffff;
 10 
 11 int head[MAXN], cost[MAXN], id[MAXN];
 12 int weight[MAXE], to[MAXE], next[MAXE];
 13 int n, ecnt;
 14 
 15 inline void init() {
 16     memset(head, 0, sizeof(head));
 17     ecnt = 2;
 18 }
 19 
 20 inline void add_edge(int u, int v, int c) {
 21     to[ecnt] = v; weight[ecnt] = c; next[ecnt] = head[u]; head[u] = ecnt++;
 22     to[ecnt] = u; weight[ecnt] = c; next[ecnt] = head[v]; head[v] = ecnt++;
 23 }
 24 
 25 int maxt[MAXN * 4];
 26 
 27 void modify(int x, int left, int right, int a, int b, int val) {
 28     if(a <= left && right <= b) maxt[x] = val;
 29     else {
 30         int ll = x << 1, rr = ll ^ 1;
 31         int mid = (left + right) >> 1;
 32         if(a <= mid) modify(ll, left, mid, a, b, val);
 33         if(mid < b) modify(rr, mid + 1, right, a, b, val);
 34         maxt[x] = max(maxt[ll], maxt[rr]);
 35     }
 36 }
 37 
 38 int query(int x, int left, int right, int a, int b) {
 39     if(a <= left && right <= b) return maxt[x];
 40     else {
 41         int ll = x << 1, rr = ll ^ 1;
 42         int mid = (left + right) >> 1, ret = 0;
 43         if(a <= mid) ret = max(ret, query(ll, left, mid, a, b));
 44         if(mid < b) ret = max(ret, query(rr, mid + 1, right, a, b));
 45         return ret;
 46     }
 47 }
 48 
 49 int size[MAXN], fa[MAXN], dep[MAXN], son[MAXN];
 50 int tid[MAXN], top[MAXN], dfs_clock;
 51 
 52 void dfs_size(int u, int f, int depth) {
 53     fa[u] = f; dep[u] = depth;
 54     size[u] = 1; son[u] = 0;
 55     int maxsize = 0;
 56     for(int p = head[u]; p; p = next[p]) {
 57         int &v = to[p];
 58         if(v == f) continue;
 59         cost[v] = weight[p];
 60         dfs_size(v, u, depth + 1);
 61         size[u] += size[v];
 62         if(size[v] > maxsize) {
 63             maxsize = size[v];
 64             son[u] = v;
 65         }
 66     }
 67 }
 68 
 69 void dfs_heavy_edge(int u, int ancestor) {
 70     tid[u] = ++dfs_clock; top[u] = ancestor;
 71     modify(1, 1, n, tid[u], tid[u], cost[u]);
 72     if(son[u]) dfs_heavy_edge(son[u], ancestor);
 73     for(int p = head[u]; p; p = next[p]) {
 74         int &v = to[p];
 75         if(v == fa[u] || v == son[u]) continue;
 76         dfs_heavy_edge(v, v);
 77     }
 78 }
 79 
 80 int query(int x, int y) {
 81     int ret = 0;
 82     while(top[x] != top[y]) {
 83         if(dep[top[x]] < dep[top[y]]) swap(x, y);
 84         ret = max(ret, query(1, 1, n, tid[top[x]], tid[x]));
 85         x = fa[top[x]];
 86     }
 87     if(dep[x] > dep[y]) swap(x, y);
 88     ret = max(ret, query(1, 1, n, tid[x] + 1, tid[y]));
 89     return ret;
 90 }
 91 
 92 void change(int x, int y) {
 93     int u = to[x], v = to[x ^ 1];
 94     if(fa[u] == v) swap(u, v);
 95     modify(1, 1, n, tid[v], tid[v], y);
 96 }
 97 
 98 char str[15];
 99 
100 int main() {
101     int T; scanf("%d", &T);
102     for(int t = 1; t <= T; ++t) {
103         scanf("%d", &n);
104         init();
105         for(int i = 1; i < n; ++i) {
106             int u, v, c;
107             scanf("%d%d%d", &u, &v, &c);
108             id[i] = ecnt;
109             add_edge(u, v, c);
110         }
111         memset(maxt, 0, sizeof(maxt));
112         dfs_size(1, 0, 0); cost[1] = -INF;
113         dfs_clock = 0;
114         dfs_heavy_edge(1, 1);
115         while(scanf("%s", str) && *str != 'D') {
116             int x, y;
117             scanf("%d%d", &x, &y);
118             if(*str == 'C') change(id[x], y);
119             else printf("%d\n", query(x, y));
120         }
121     }
122 }

View Code

 代码（3400MS）（加了个IO优化……）：

  1 #include <cstdio>
  2 #include <iostream>
  3 #include <algorithm>
  4 #include <cstring>
  5 #include <cctype>
  6 using namespace std;
  7 
  8 const int MAXN = 10010;
  9 const int MAXE = 2 * MAXN;
 10 const int INF = 0x7fffffff;
 11 
 12 int head[MAXN], cost[MAXN], id[MAXN];
 13 int weight[MAXE], to[MAXE], next[MAXE];
 14 int n, ecnt;
 15 
 16 inline void init() {
 17     memset(head, 0, sizeof(head));
 18     ecnt = 2;
 19 }
 20 
 21 inline void add_edge(int u, int v, int c) {
 22     to[ecnt] = v; weight[ecnt] = c; next[ecnt] = head[u]; head[u] = ecnt++;
 23     to[ecnt] = u; weight[ecnt] = c; next[ecnt] = head[v]; head[v] = ecnt++;
 24 }
 25 
 26 int maxt[MAXN * 4];
 27 
 28 void modify(int x, int left, int right, int a, int b, int val) {
 29     if(a <= left && right <= b) maxt[x] = val;
 30     else {
 31         int ll = x << 1, rr = ll ^ 1;
 32         int mid = (left + right) >> 1;
 33         if(a <= mid) modify(ll, left, mid, a, b, val);
 34         if(mid < b) modify(rr, mid + 1, right, a, b, val);
 35         maxt[x] = max(maxt[ll], maxt[rr]);
 36     }
 37 }
 38 
 39 int query(int x, int left, int right, int a, int b) {
 40     if(a <= left && right <= b) return maxt[x];
 41     else {
 42         int ll = x << 1, rr = ll ^ 1;
 43         int mid = (left + right) >> 1, ret = 0;
 44         if(a <= mid) ret = max(ret, query(ll, left, mid, a, b));
 45         if(mid < b) ret = max(ret, query(rr, mid + 1, right, a, b));
 46         return ret;
 47     }
 48 }
 49 
 50 int size[MAXN], fa[MAXN], dep[MAXN], son[MAXN];
 51 int tid[MAXN], top[MAXN], dfs_clock;
 52 
 53 void dfs_size(int u, int f, int depth) {
 54     fa[u] = f; dep[u] = depth;
 55     size[u] = 1; son[u] = 0;
 56     int maxsize = 0;
 57     for(int p = head[u]; p; p = next[p]) {
 58         int &v = to[p];
 59         if(v == f) continue;
 60         cost[v] = weight[p];
 61         dfs_size(v, u, depth + 1);
 62         size[u] += size[v];
 63         if(size[v] > maxsize) {
 64             maxsize = size[v];
 65             son[u] = v;
 66         }
 67     }
 68 }
 69 
 70 void dfs_heavy_edge(int u, int ancestor) {
 71     tid[u] = ++dfs_clock; top[u] = ancestor;
 72     modify(1, 1, n, tid[u], tid[u], cost[u]);
 73     if(son[u]) dfs_heavy_edge(son[u], ancestor);
 74     for(int p = head[u]; p; p = next[p]) {
 75         int &v = to[p];
 76         if(v == fa[u] || v == son[u]) continue;
 77         dfs_heavy_edge(v, v);
 78     }
 79 }
 80 
 81 int query(int x, int y) {
 82     int ret = 0;
 83     while(top[x] != top[y]) {
 84         if(dep[top[x]] < dep[top[y]]) swap(x, y);
 85         ret = max(ret, query(1, 1, n, tid[top[x]], tid[x]));
 86         x = fa[top[x]];
 87     }
 88     if(dep[x] > dep[y]) swap(x, y);
 89     ret = max(ret, query(1, 1, n, tid[x] + 1, tid[y]));
 90     return ret;
 91 }
 92 
 93 void change(int x, int y) {
 94     int u = to[x], v = to[x ^ 1];
 95     if(fa[u] == v) swap(u, v);
 96     modify(1, 1, n, tid[v], tid[v], y);
 97 }
 98 
 99 char str[15];
100 
101 inline int readint() {
102     char c = getchar();
103     while(!isdigit(c)) c = getchar();
104     int ret = 0;
105     while(isdigit(c)) ret = ret * 10 + c - '0', c = getchar();
106     return ret;
107 }
108 
109 int main() {
110     int T = readint();
111     for(int t = 1; t <= T; ++t) {
112         n = readint();
113         init();
114         for(int i = 1; i < n; ++i) {
115             int u = readint(), v = readint(), c = readint();
116             id[i] = ecnt;
117             add_edge(u, v, c);
118         }
119         memset(maxt, 0, sizeof(maxt));
120         dfs_size(1, 0, 0); cost[1] = -INF;
121         dfs_clock = 0;
122         dfs_heavy_edge(1, 1);
123         while(scanf("%s", str) && *str != 'D') {
124             int x = readint(), y = readint();
125             if(*str == 'C') change(id[x], y);
126             else printf("%d\n", query(x, y));
127         }
128     }
129 }

View Code

 

转载于:https://www.cnblogs.com/oyking/p/3339607.html