PHP与Javascript的混合测试

js调用php

<?php
 $num=88;
?>

<script>
 var a = <?php echo $num;?>;
 alert(a);
</script>

 

 

php调用js

<?php
 $num = 88;
 echo "<script>alert( $num )</script>";
?>

 

转载于:https://www.cnblogs.com/roluce/p/6030483.html