SPOJ 10234. Here Be Dragons

本文介绍了一个基于哈利波特三强争霸赛灵感的编程挑战,玩家需要帮助哈利通过布满龙的走廊,达到终点。文章提供了输入输出示例及限制条件,并附带了C++实现代码。

The Triwizard Tournament's third task is to negotiate a corridor of many segments, and reach the other end. The corridor is N segments long. The ith segment is either empty or has a dragon. Harry cannot pass the dragon and will have no option but to retreat if he encounters one. Is it possible for him to reach the exit starting from the entrance?

Input (STDIN):
The first line contains the number of test cases T.
Each of the next T lines contains a string describing the corridor. The ith character is either a '.' if the segment is empty, or a 'D' if the segment contains a dragon.
Output (STDOUT):
Output T lines, each containing either the string "Possible" if you can reach the exit, and "You shall not pass!" if it is not possible to reach the exit.
Constraints:
1 <= T <= 50
1 <= N <= 50
Time Limit: 1 s
Memory Limit: 32 MB
Sample Input:
3
..
..D.
D..D
Sample Output:
Possible
You shall not pass!
You shall not pass!

 

The Triwizard Tournament's third task is to negotiate a corridor of many segments, and reach the other end. The corridor is N segments long. The ith segment is either empty or has a dragon. Harry cannot pass the dragon and will have no option but to retreat if he encounters one. Is it possible for him to reach the exit starting from the entrance?

 

Input (STDIN):

The first line contains the number of test cases T.

Each of the next T lines contains a string describing the corridor. The ith character is either a '.' if the segment is empty, or a 'D' if the segment contains a dragon.

 

Output (STDOUT):

Output T lines, each containing either the string "Possible" if you can reach the exit, and "You shall not pass!" if it is not possible to reach the exit.

 

Constraints:

1 <= T <= 50

1 <= N <= 50

 

Sample Input:

3

..

..D.

D..D

 

Sample Output:

Possible

You shall not pass!

You shall not pass!

 1 #include<iostream>  
 2 #include<string.h>  
 3 #include<stdio.h>  
 4 #include<ctype.h>  
 5 #include<algorithm>  
 6 #include<stack>  
 7 #include<queue>  
 8 #include<set>  
 9 #include<math.h>  
10 #include<vector>  
11 #include<map>  
12 #include<deque>  
13 #include<list>  
14 using namespace std;  
15 int main()
16 {
17     char a[100];
18     int n,flag=0;
19     scanf("%d",&n);
20     for(int i=0;i<n;i++)
21     {
22         flag=1;
23         cin>>a;
24         int m=strlen(a);
25         for(int l=0;l<m;l++)
26         {
27             if(a[l]=='D')
28             {
29             flag=-1;
30             printf("You shall not pass!\n");
31             break;
32             }
33         } 
34         if(flag==1)
35         printf("Possible\n");
36     }
37     return 0;
38 } 
View Code

转载于:https://www.cnblogs.com/qscqesze/p/3856462.html

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