674. Longest Continuous Increasing Subsequence

本文介绍了一种求解未排序整数数组中最长连续递增子序列长度的方法,并给出C++实现示例。通过遍历数组并使用变量记录当前递增子序列长度及最大长度,最终返回最大长度。

Given an unsorted array of integers, find the length of longest continuous increasing subsequence.

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4. 

 

Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 

在未排序的数组中,找出最长递增序列的长度

 

c++(16ms):

 1 class Solution {
 2 public:
 3     int findLengthOfLCIS(vector<int>& nums) {
 4                 int len  = nums.size() ;
 5         if (len < 1)
 6             return 0 ;
 7         int Max = 1 ;
 8         int n = 1 ;
 9         for (int i = 0 ; i < len-1 ; i++){
10             if (nums[i] < nums[i+1])
11                 n++ ;
12             else
13                 n = 1 ;
14             if (n > Max)
15                 Max = n ;
16         }
17         return Max ;
18     }
19 };

 

转载于:https://www.cnblogs.com/mengchunchen/p/7531542.html

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