字符串转化并累加

    一行字符类型的数字，每个数字以空格隔开，将它们转化为数字后累加求和

 

 1 #include <iostream>
 2 #include <string>
 3 #include <sstream>
 4 using namespace std;
 5 
 6 int main() {
 7     string str;
 8     while (getline(cin, str)) {
 9         int sum = 0, num = 0;
10         stringstream ssio(str);
11         while (ssio >> num)
12             sum += num;
13         cout << sum << endl;
14     }
15 
16     return 0;
17 }

 

转载于:https://www.cnblogs.com/moujun1001/p/9741013.html