codeforces 97 div2 C.Replacement 水题-优快云博客

本文详细阐述了如何通过替换数组中的一个元素来使其字典序最小化的算法，并提供了实现代码。重点介绍了在数组中寻找最大值进行替换的策略，以及在特定场景下如全数组元素为1时的特殊处理。

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Little Petya very much likes arrays consisting of n integers, where each of them is in the range from 1 to 109, inclusive. Recently he has received one such array as a gift from his mother. Petya didn't like it at once. He decided to choose exactly one element from the array and replace it with another integer that also lies in the range from 1 to 109, inclusive. It is not allowed to replace a number with itself or to change no number at all.

After the replacement Petya sorted the array by the numbers' non-decreasing. Now he wants to know for each position: what minimum number could occupy it after the replacement and the sorting.

Input

The first line contains a single integer n (1 ≤ n ≤ 105), which represents how many numbers the array has. The next line contains nspace-separated integers — the array's description. All elements of the array lie in the range from 1 to 109, inclusive.

Output

Print n space-separated integers — the minimum possible values of each array element after one replacement and the sorting are performed.

Examples

input

5
1 2 3 4 5

output

1 1 2 3 4

input

5
2 3 4 5 6

output

1 2 3 4 5

input

3
2 2 2

output

1 2 2
题意：改变一个数使得字典序最小；
思路：改变最大值；全是1是坑点；

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 #define ll __int64
 4 #define mod 1000000007
 5 #define inf 100000000000005
 6 #define MAXN 10000010
 7 //#pragma comment(linker, "/STACK:102400000,102400000")
 8 int a[100010];
 9 int main()
10 {
11     int x,y,z,i,t;
12     scanf("%d",&x);
13     for(i=0;i<x;i++)
14     scanf("%d",&a[i]);
15     sort(a,a+x);
16     if(a[x-1]!=1)
17     a[x-1]=1;
18     else
19     a[x-1]=2;
20     sort(a,a+x);
21     for(i=0;i<x;i++)
22     printf("%d ",a[i]);
23     return 0;
24 }