uva 1001（floyd）

依旧板子题

#include <iostream>
#include <cstring>
#include <algorithm>
#include <cstdio>
#include <queue>
#include <cmath>
using namespace std;
const int maxn=100+10;
double g[maxn][maxn];
const int inf=0x3f3f3f3f;
struct node
{
    double x,y,z;
    double r;
}bb[maxn];
double getw(node a,node b)
{
    double mm=(a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)+(a.z-b.z)*(a.z-b.z);
     double nn=sqrt(mm)-a.r-b.r;
     if(nn<0) nn=0;
     return nn;
}
int n;
int main()
{
//    freopen("in.txt","r",stdin);
//    freopen("out.txt","w",stdout);
    int Case=0;
    while(~scanf("%d",&n))
    {
        if(n==-1) break;
        for(int i=1;i<=n;i++)
        {
          scanf("%lf%lf%lf%lf",&bb[i].x,&bb[i].y,&bb[i].z,&bb[i].r);
        }
        n=n+2;
        for(int i=n-1;i<=n;i++)
        {
            scanf("%lf%lf%lf",&bb[i].x,&bb[i].y,&bb[i].z);
            bb[i].r=0;
        }
        for(int i=1;i<=n;i++)
          for(int j=1;j<=n;j++)
        {
            g[i][j]=getw(bb[i],bb[j]);
        }
        for(int k=1;k<=n;k++)
            for(int i=1;i<=n;i++)
               for(int j=1;j<=n;j++)
                  g[i][j]=min(g[i][j],g[i][k]+g[k][j]);
        printf("Cheese %d: Travel time = %.0f sec\n",++Case,floor(g[n-1][n]*10.0+0.5));
    }
    return 0;
}

 

转载于:https://www.cnblogs.com/Wangwanxiang/p/8360627.html