LeetCode - 461. Hamming Distance

本文介绍了如何计算两个整数之间的汉明距离,并提供了一种高效算法。通过使用按位与运算,可以在较短时间内得出结果。文章包含Python及C++实现代码。

Description

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Note:
0 ≤ x, y < 231.

Example:

Input: x = 1, y = 4

Output: 2

Explanation:
1 (0 0 0 1)
4 (0 1 0 0)

The above arrows point to positions where the corresponding bits are different.

Solution

除了最容易想到的暴力法,还可以用n与n-1按位与的方法

python版:

class Solution(object):
    def hammingDistance(self, x, y):
        """
        :type x: int
        :type y: int
        :rtype: int
        """
        xor = x ^ y
        count = 0
        while (xor != 0):
            xor = xor & (xor - 1)
            count = count + 1
        
        return count

cpp版:

class Solution {
public:
    int hammingDistance(int x, int y)
    {
        int xor_diff = x ^ y;
        int count = 0;
        while (xor_diff != 0)
        {
            count++;
            xor_diff = xor_diff & (xor_diff-1);
        }
        return count;
    }
};

Reference:

转载于:https://www.cnblogs.com/gxcdream/p/7500540.html

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