作业2-习题2.4

#include<stdio.h>
int main(void)
{
    int m,n;
    double i,y;
    y=1;
    printf("输入m，n的值：");
    scanf("%d%d",&m,&n);
    for(i=m;i<=n;i++){
        y=y+(i*i+1/i);
    }
    printf("y=%Lf",y);
    return 0;
}

转载于:https://www.cnblogs.com/simple9495/p/3378633.html