Burning Midnight Oil

夜间编程挑战
本文介绍了一个编程问题:在生产力随时间递减的情况下,如何计算完成指定规模程序所需的最小初始工作效率。通过二分查找的方法找到了最优解。
E - Burning Midnight Oil
Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

Description

One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of n lines of code. Vasya is already exhausted, so he works like that: first he writes v lines of code, drinks a cup of tea, then he writes as much as  lines, drinks another cup of tea, then he writes  lines and so on: , ...

The expression  is regarded as the integral part from dividing number a by number b.

The moment the current value  equals 0, Vasya immediately falls asleep and he wakes up only in the morning, when the program should already be finished.

Vasya is wondering, what minimum allowable value v can take to let him write not less than n lines of code before he falls asleep.

Input

The input consists of two integers n and k, separated by spaces — the size of the program in lines and the productivity reduction coefficient, 1 ≤ n ≤ 1092 ≤ k ≤ 10.

Output

Print the only integer — the minimum value of v that lets Vasya write the program in one night.

Sample Input

Input
7 2
Output
4
Input
59 9
Output
54
二分,看加起来够不够,这个代码参考了一下,很巧妙,之前我还傻逼的用pow算指数,二比了

转载于:https://www.cnblogs.com/wejex/p/3218793.html

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