Compare Version Numbers

最新推荐文章于 2024-08-02 16:45:34 发布

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最新推荐文章于 2024-08-02 16:45:34 发布

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原文链接：http://www.cnblogs.com/beiyeqingteng/p/5743235.html

本文介绍了一种用于比较两个版本号大小的方法。通过将版本号字符串拆分为数组，并逐位比较每个数字来确定版本间的大小关系。该算法适用于软件版本管理和更新检查等场景。

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Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

 1 public class Solution {
 2     public int compareVersion(String version1, String version2) {
 3         String[] levels1 = version1.split("\\.");
 4         String[] levels2 = version2.split("\\.");
 5 
 6         int length = Math.max(levels1.length, levels2.length);
 7         for (int i = 0; i < length; i++) {
 8             Integer v1 = i < levels1.length ? Integer.parseInt(levels1[i]) : 0;
 9             Integer v2 = i < levels2.length ? Integer.parseInt(levels2[i]) : 0;
10             int compare = v1.compareTo(v2);
11             if (compare != 0) {
12                 return compare;
13             }
14         }
15         return 0;
16     }
17 }