Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not “two and a half” or “half way to version three”, it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
Credits:
Special thanks to @ts for adding this problem and creating all test cases.

本文探讨如何比较两个版本号version1和version2。若version1大于version2返回1,小于则返回-1,相等则返回0。版本号由数字和'.'组成,'.'不是小数点,而是分隔符。例如,2.5表示第二个一级修订的第五个二级修订。文章列举了版本号比较的各种情况,并给出了解决方案,包括处理0的特殊情况和使用split('.')的注意事项。
订阅专栏 解锁全文
1138

被折叠的 条评论
为什么被折叠?



