PAT 1117 Eddington Number

最新推荐文章于 2020-05-10 19:40:11 发布

weixin_30583563

最新推荐文章于 2020-05-10 19:40:11 发布

阅读量136

点赞数

CC 4.0 BY-SA版权

原文链接：http://www.cnblogs.com/A-Little-Nut/p/9502057.html

本文介绍了一种基于天文学家Eddington骑行习惯定义的独特数值——Eddington数，并提供了一个C++程序来计算给定一系列骑行距离后的Eddington数。

British astronomer Eddington liked to ride a bike. It is said that in order to show off his skill, he has even defined an "Eddington number", E -- that is, the maximum integer E such that it is for E days that one rides more than E miles. Eddington's own E was 87.

Now given everyday's distances that one rides for N days, you are supposed to find the corresponding E (≤N).

Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤10^5 ), the days of continuous riding. Then N non-negative integers are given in the next line, being the riding distances of everyday.

Output Specification:
For each case, print in a line the Eddington number for these N days.

Sample Input:
10
6 7 6 9 3 10 8 2 7 8

Sample Output:
6

#include <iostream>
#include <algorithm>
using namespace std;
int a[1000000];
int main() {
    int n, e = 0;
    scanf("%d", &n);
    for(int i = 0; i < n; i++)
        scanf("%d", &a[i]);
    sort(a, a+n, greater<int>());
    while(e < n && a[e] > e+1) e++;
    printf("%d", e);
    return 0;
}

转载于:https://www.cnblogs.com/A-Little-Nut/p/9502057.html