【PAT】A1117 Eddington Number 【排序】

该博客介绍了Eddington Number的概念,即寻找连续骑行天数中,每天骑行距离大于天数的最大整数E。通过给出的骑行天数N和每天的骑行距离,博客提供了一种算法思路:将距离数组降序排列,然后检查每个元素是否大于当前E值加1,来找到满足条件的最大E值。给出了样例输入和输出,以及解题思路和代码实现。

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British astronomer Eddington liked to ride a bike. It is said that in order to show off his skill, he has even defined an “Eddington number”, E – that is, the maximum integer E such that it is for E days that one rides more than E miles. Eddington’s own E was 87.

Now given everyday’s distances that one rides for N days, you are supposed to find the corresponding E (≤N).

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤10^​5), the days of continuous riding. Then N non-negative integers are given in the next line, being the riding distances of everyday.

Output Specification:

For each case, print in a line the Eddington number for these N days.

Sample Input:

10
6 7 6 9 3 10 8 2 7 8

Sample Output:

6

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