C++学习之2--10.09题目答案-优快云博客

6.12.cpp

/**//****************************

homework 6.12

Author : Ray

Question: Calculate Charges

Data : 2008.10.08

*****************************/

#include <iostream>

using std::cin;

using std::cout;

using std::endl;

using std::fixed;

#include <iomanip>

using std::setw;

using std::setprecision;

double calculateCharges(double hours)

{

if(hours<=0)

{

return 0;

}else if(hours<=3)

{

return 2;

}else if(hours<24)

{

double money;

money=2+0.5*(hours-3);

if(money>10)

{

return 10;

}else

{

return money;

}

#define CARNUMBER 3

void main()

{

double hours[CARNUMBER];

cout<<"please input the used hours of "<<CARNUMBER<<" cars:";

int i=0;

for(i=0;i<CARNUMBER;i++)

{

cin>>hours[i];

}

double totalHours=0,totalMoney=0,money;

cout<<"Car\t"<<setw(5)<<"Hours\t"<<setw(6)<<"Charge"<<endl;

for(i=0;i<CARNUMBER;i++)

{

money=calculateCharges(hours[i]);

totalHours+=hours[i];

totalMoney+=money;

cout<<i<<"\t"

<<setw(5)<<fixed<<setprecision(2)<<hours[i]<<"\t"

<<setw(5)<<fixed<<setprecision(2)<<money<<endl;

}

cout<<"Total\t"<<setw(5)<<totalHours<<"\t"<<setw(5)<<totalMoney<<endl;

}

/**//*************************************************

Results:

please input the used hours of 3 cars:2 4.5 22.3

Car Hours Charge

0 2.00 2.00

1 4.50 2.75

2 22.30 10.00

Total 28.80 14.75

Attentions:

1.如何处理处理对齐

2.如何处理小数精确度

3.对0和负数的判断

*************************************************/

6.29.cpp

/**//****************************

homework 6.29

Author : Ray

Question: Perfect Numbers

Data : 2008.10.08

*****************************/

#include <iostream>

using std::cin;

using std::cout;

using std::endl;

bool perfect(int number)

{

int sum=0;

for(int i=1;i<number;i++)

{

if(0==number%i)

{

sum+=i;

}

if(sum==number)

{

return true;

}else

{

return false;

}

#define MAXNUMBER 10000

void main()

{

cout<<"Perfect Numbers: ";

for(int i=2;i<=MAXNUMBER;i++)

{

if(perfect(i))

{

cout<<i<<"\t";

}

cout<<endl;

}

/**//*************************************************

Results:

Perfect Numbers: 6 28 496 8128

Attentions:

None

*************************************************/

6.31.cpp

/**//****************************

homework 6.31

Author : Ray

Question: Reverse Digits

Data : 2008.10.08

*****************************/

#include <iostream>

using std::cin;

using std::cout;

using std::endl;

int reverse(int number)

{

int div = number/10;//前面n-1位

int digit = number%10;//最后一位

int ret = 0;//返回值

while(0!=div)

{

ret=ret*10+digit;//向最后插入一位数字

digit=div%10;

div=div/10;

}

ret=ret*10+digit;

return ret;

}

void main()

{

int input;

cout<<"Input an integer(0<n<=65535)\t:";

cin>>input;

cout<<"Reverse number\t\t\t:"<<reverse(input)<<endl;

}

/**//*************************************************

Results:

Input an integer(0<n<=65535) :23451

Reverse number :15432

Attentions:

1.注意一下reverse算法，很多人使用10的幂函数和数组来存储，其实是没有必要的

*************************************************/

6.42.cpp

/**//****************************

homework 6.42

Author : Ray

Question: Towers of Hanoi

Data : 2008.10.08

*****************************/

#include <iostream>

using std::cin;

using std::cout;

using std::endl;

void move(int oldPeg,int newPeg)

{

cout<<oldPeg<<"\t--->\t"<<newPeg<<endl;

}

void move(int number,int oldPeg,int newPeg,int tmpPeg)

{

if(1==number)//directly move

{

print(oldPeg,newPeg);

}else

{

move(number-1,oldPeg,tmpPeg,newPeg);

move(1,oldPeg,newPeg,tmpPeg);

move(number-1,tmpPeg,newPeg,oldPeg);

}

void main()

{

int num;

cout<<"Input the numbers of the disks:";

cin>>num;

move(num,1,3,2);

}

/**//*************************************************

Results:

Input the numbers of the disks:3

1 ---> 3

1 ---> 2

3 ---> 2

1 ---> 3

2 ---> 1

2 ---> 3

1 ---> 3

Attentions:

1.了解递归的用法即可

*************************************************/

4.42.new.cpp

/**//****************************

homework 6.42.new

Author : Ray

Question: Towers of Hanoi

Data : 2008.10.08

Image display !

*****************************/

#include <iostream>

using std::cin;

using std::cout;

using std::endl;

using std::left;

using std::right;

#include <string>

using std::string;

#define MAXDISKS 64

int num;

//用户输入盘子数目

int table[3][MAXDISKS];

//数组，三根柱子，每个单元表示有盘子号，-1表示没有

/**//*

组织成星星字符串

int n: 星星的半数

int mid: 星星的中间位置

*/

string getStar(int n,int mid)

{

string rtn("");

int i;

for(i=0;i<mid-n;i++)

{

rtn+=" ";

}

for(;i<mid+n;i++)

{

rtn+="*";

}

for(;i<mid*2;i++)

{

rtn+=" ";

}

return rtn;

}

//将数组里面的图画出来

void draw()

{

int i;

int j;

for(i=num;i>=0;i--)

{

for(j=0;j<3;j++)

{

cout<<getStar(table[j][i]+1,num+2);

}

cout<<endl;

}

cout<<"------------------------------------------------"<<endl;

}

//Reconstruction.

void move(int oldPeg,int newPeg)

{

int i=num;

int j=num;

//找到最上层

while(table[oldPeg-1][i]==-1 && i>0)

{

i--;

}

while(table[newPeg-1][j]==-1 && j>=0)

{

j--;

}

//搬过来

table[newPeg-1][j+1]=table[oldPeg-1][i];

table[oldPeg-1][i]=-1;

cout<<" "<<oldPeg<<"\t--->\t"<<newPeg<<endl;

draw();

}

void move(int number,int oldPeg,int newPeg,int tmpPeg)

{

if(1==number)//directly move

{

move(oldPeg,newPeg);

}else

{

move(number-1,oldPeg,tmpPeg,newPeg);

move(1,oldPeg,newPeg,tmpPeg);

move(number-1,tmpPeg,newPeg,oldPeg);

}

void main()

{

cout<<"Input the numbers of the disks(<=64):";

cin>>num;

//初始化

int i,j;

for(i=0;i<3;i++)

{

for(j=0;j<MAXDISKS;j++)

{

table[i][j]=-1;

}

//0号盘放在上面

i=0;

for(j=num-1;j>=0;j--)

{

table[0][j]=i;

i++;

}

draw();

move(num,1,3,2);

}

/**//*************************************************

Results:

Input the numbers of the disks(<=64):3

**

****

******

------------------------------------------------

1 ---> 3

****

****** **

------------------------------------------------

1 ---> 2

****** **** **

------------------------------------------------

3 ---> 2

**

****** ****

------------------------------------------------

1 ---> 3

**

**** ******

------------------------------------------------

2 ---> 1

** **** ******

------------------------------------------------

2 ---> 3

****

** ******

------------------------------------------------

1 ---> 3

**

****

******

------------------------------------------------

Attentions:

1.画图比较麻烦，可以了解一下

2.数据的结构有很多种方式，但是简单的数组会导致复杂的画图，所以可以权衡一下

*************************************************/

6.47.cpp

/**//****************************

homework 6.47

Author : Ray

Question: a computer-assisted instruction program

Data : 2008.10.08

*****************************/

#include <iostream>

using std::cin;

using std::cout;

using std::endl;

using std::fixed;

#include <string>

using std::string;

#include <iomanip>

using std::setprecision;

#include <stdlib.h>

#include <time.h>

#define QNUM 10//题目数量

int level=0,type=0,count=0;;

void displayLevel()

{

cout<<"**************************************\n";

cout<<" WELCOME TO \n";

cout<<" Computer Assisted Instruction \n";

cout<<"**************************************\n";

cout<<endl;

cout<<".SELECT A LEVEL\n";

cout<<" 1 - level 1, one-digit integers\n";

cout<<" 2 - level 2, two-digit integers\n";

cin>>level;

while(level<1 || level>2)

{

cout<<"Wrong level! Try again

"<<endl;

cin>>level;

}

void displayType()

{

cout<<"\n.SELECT A TYPE\n";

cout<<" 1 - Addition\n";

cout<<" 2 - Subtraction\n";

cout<<" 3 - Multiplication\n";

cout<<" 4 - Division\n";

cout<<" 5 - All types\n";

cin>>type;

while(type<1||type>5)

{

cout<<"Wrong level! Try again

"<<endl;

cin>>type;

}

string rspA[]=

{"Very good!"

,"Excellent!"

,"Nice work!"

,"Keep up the good work!"};

string rspB[]=

{"No. Please try again."

,"Wrong. Try once more."

,"Don't give up!"

,"No. Keep trying."};

enum Response

{GOOD,BAD};

void responses(Response r)

{

int i = rand()%4;

switch(r)

{

case GOOD:

cout<<rspA[i]<<endl;

count++;

break;

case BAD:

cout<<rspB[i]<<endl;

break;

default:

break;

};

}

void displayResults()

{

double ratio = count/(double)QNUM;

cout<<"\n---------------------------------------\n";

cout<<".RESULTS \n";

cout<<"Questions\t: "<<QNUM<<endl;

cout<<"Correct \t: "<<count<<endl;

cout<<"Ratio \t: "<<setprecision(4)<<ratio*100<<"%\n";

cout<<"---------------------------------------\n\n";

if(ratio<0.75)

{

cout<<"Please ask your instructor for extra help!\n";

}else

{

cout<<"You pass the Exam !\n";

}

cout<<"\n**************************************\n";

cout<<" GOOD BYE \n";

cout<<"**************************************\n";

}

int createNumber()

{

switch(level)

{

case 1:

return 1+rand()%9;

default:

return 1+rand()%99;

}

void add()

{

int r;

int n=createNumber();

int m=createNumber();

cout<<m<<"+"<<n<<"=";

cin>>r;

if(r==m+n)

{

responses(GOOD);

}else

{

responses(BAD);

}

void sub()

{

int r;

int n=createNumber();

int m=createNumber();

if(m<n)

{

r=n;

n=m;

m=r;

}

cout<<m<<"-"<<n<<"=";

cin>>r;

if(r==m-n)

{

responses(GOOD);

}else

{

responses(BAD);

}

void mul()

{

int r;

int n=createNumber();

int m=createNumber();

cout<<m<<"x"<<n<<"=";

cin>>r;

if(r==m*n)

{

responses(GOOD);

}else

{

responses(BAD);

}

void div()

{

int r;

int n=createNumber();

int m=createNumber();

r=n*m;

cout<<r<<"/"<<m<<"=";

cin>>m;

if(m==n)

{

responses(GOOD);

}else

{

responses(BAD);

}

void question(int i)

{

cout<<"\n("<<i+1<<")\t";

int t=type;

if(type==5)

{

t=1+rand()%5;

}

switch(t)

{

case 1:add();break;

case 2:sub();break;

case 3:mul();break;

default:div();

}

void main()

{

displayLevel();

displayType();

srand(time(0));

cout<<"\n.OK. Let’s begin

\n";

cout<<"---------------------------------------\n";

int i;

for(i=0;i<QNUM;i++)

{

question(i);

}

displayResults();

}

/**//*************************************************

Results:

**************************************

WELCOME TO

Computer Assisted Instruction

**************************************

.SELECT A LEVEL

1 - level 1, one-digit integers

2 - level 2, two-digit integers

1

.SELECT A TYPE

1 - Addition

2 - Subtraction

3 - Multiplication

4 - Division

5 - All types

5

.OK. Lets Begin

---------------------------------------

(1) 16/8=2

Very good!

(2) 1/1=1

Nice work!

(3) 6+6=12

Very good!

(4) 35/5=7

Excellent!

(5) 14/7=2

Nice work!

(6) 12/2=6

Nice work!

(7) 5-2=3

Excellent!

(8) 8-2=6

Nice work!

(9) 7+9=16

Excellent!

(10) 4-4=0

Very good!

---------------------------------------

.RESULTS

Questions : 10

Correct : 10

Ratio : 100%

---------------------------------------

You pass the Exam !

**************************************

GOOD BYE

**************************************

Attentions:

1.减法注意两个数的大小，除法应该要能整除

2.内容较多，注意函数的应用，条理清楚

*************************************************/

宾果游戏

/**//****************************

homework

Author : Ray

Question: Bingo

Data : 2008.10.08

*****************************/

#include <iostream>

using std::cin;

using std::cout;

using std::endl;

#include <stdlib.h>

#include <time.h>

void main()

{

int number[4];

srand(time(0));

//create 4 numbers

int i=1;

number[0]=1+rand()%9;

while(i<4)

{

number[i]=0+rand()%10;

bool isSame = false;

for(int j=0;j<i;j++)

{

if(number[i]==number[j])

{

isSame=true;

break;

}

if(!isSame)

{

i++;

}

cout<<number[0]<<number[1]<<number[2]<<number[3]<<endl;

cout<<"**********************"<<endl;

cout<<" Bingo Game"<<endl;

cout<<"**********************"<<endl;

//guess the number

int input,guess[4],t,j;

for(t=0;t<16;t++)

{

cout<<"Input a number(4 digits):";

cin>>input;

while(input<1000 || input>9999)

{

cout<<"Wrong number. Try again."<<endl;

cout<<"Input a number(4 digits):";

cin>>input;

}

//分解

j=2;

int div = input/10;

guess[3] = input%10;

while(div!=0)

{

guess[j]=div%10;

div/=10;

j--;

}

//比较

int a=0,b=0;

for(i=0;i<4;i++)

{

if(guess[i]==number[i])

{

a++;

}else

{

for(j=0;j<4;j++)

{

if(guess[i]==number[j])

{

b++;

}

if(a==4)

{

cout<<"You Win !"<<endl;

return;

}else if(t<16)

{

cout<<a<<"A"<<b<<"B"<<endl;

cout<<16-t-1 <<" times left. Try again

\n";

}

cout<<"You Lost !"<<endl;

}

/**//*************************************************

Results:

7865

**********************

Bingo Game

**********************

Input a number(4 digits):1234

0A0B

15 times left. Try again

Input a number(4 digits):5678

0A4B

14 times left. Try again

Input a number(4 digits):6587

0A4B

13 times left. Try again

Input a number(4 digits):7856

2A2B

12 times left. Try again

Input a number(4 digits):8756

0A4B

11 times left. Try again

Input a number(4 digits):7865

You Win !

Press any key to continue

Attentions:

1.主要是随机数和循环结构的应用

2.没有使用函数，因为需要使用指针

3.数字的分解与判断

*************************************************/