[LeetCode] Assign Cookies

本文介绍了一个经典的分配问题:如何最大化满足孩子的数量,每个孩子有一个贪婪系数,每块饼干有一个大小,目标是找到一种分配方式使得尽可能多的孩子满意。通过排序和双指针法解决了这一问题。

Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.

Note:
You may assume the greed factor is always positive. 
You cannot assign more than one cookie to one child.

Example 1:

Input: [1,2,3], [1,1]

Output: 1

Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. 
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.

Example 2:

Input: [1,2], [1,2,3]

Output: 2

Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. 
You have 3 cookies and their sizes are big enough to gratify all of the children, 
You need to output 2.
找出饼干尺寸比贪婪因素大的个数,首先将两个数组排序,然后使用两个索引查找符合要求的值,如果找到则两个索引都+1,如果没找到,则让饼干尺寸的索引+1。
class Solution {
public:
    int findContentChildren(vector<int>& g, vector<int>& s) {
        sort(g.begin(), g.end());
        sort(s.begin(), s.end());
        int res = 0, tmp = 0;
        while (res != g.size() && tmp != s.size()) {
            if (g[res] <= s[tmp]) {
                res++;
                tmp++;
            }
            else
                tmp++;
        }
        return res;
    }
};
// 43 ms

 

转载于:https://www.cnblogs.com/immjc/p/7168820.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值