AjaxHelper学习，ajax,microsoft,mvc,asp.net

最新推荐文章于 2025-09-12 17:02:52 发布

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最新推荐文章于 2025-09-12 17:02:52 发布

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文章标签：测试 json

原文链接：http://www.cnblogs.com/bushuosx/p/3911165.html

本文展示了如何在ASP.NET MVC中利用Ajax进行跨页面数据交互，包括发送请求到服务器、处理服务器响应并更新页面内容。通过具体代码实例，详细介绍了使用Ajax.BeginForm和Ajax.ActionLink的方法，以及如何在客户端通过脚本处理服务器返回的数据。

index.cshtml

@using (Ajax.BeginForm("ContentAjax", new AjaxOptions { UpdateTargetId = "pajax" }))
{
    <div>
        <p id="pajax"></p>
        <input class="text" name="username" />
        <button class="btn-default">ContentAjax测试</button>
    </div>
}

<div>
    @Ajax.ActionLink("JsonAjax测试", "JsonAjax", new AjaxOptions { OnSuccess = "jsonshow" })
</div>

<script>
    function jsonshow(data)
    {
        $("#pajax").html("用户ID：" + data.id + "<br/>"
            + "姓名：" + data.name + "<br/>"
            + "Email：" + data.email);
    }
</script>

<div>
    @Ajax.ActionLink("PartialViewAjax测试", "PartialViewAjax", new AjaxOptions { UpdateTargetId = "pajax" })
</div>

@section Scripts{
    @Scripts.Render("~/bundles/jqueryval")
}

HomeController.cs

public ActionResult Index()
        {
            return View();
        }

        public ActionResult ContentAjax(string username)
        {
            return Content("Content：" + "<br>" + "用户名：" + username);
        }

        public ActionResult JsonAjax()
        {
            UserInfo user = new UserInfo { id = 1, name = "Json", email = "json@qq.com" };
            return Json(user, JsonRequestBehavior.AllowGet);
        }

        public ActionResult PartialViewAjax()
        {
            UserInfo user = new UserInfo { id = 2, name = "PartialView", email = "PartialViewAjax@qq.com" };
            return PartialView("PartialViewAjax",user);
        }

PartialViewAjax.cshtml

@model MvcBasic.Models.UserInfo
<p>
    用户ID：@Model.id
    <br/>
    姓名：@Model.name
    <br/>
    Email：@Model.email
</p>

Model

public class UserInfo
    {
        public int id { get; set; }

        public string name { get; set; }

        public string email { get; set; }
    }