717. 1-bit and 2-bit Characters

1. Question

717. 1-bit and 2-bit Characters

https://leetcode.com/problems/1-bit-and-2-bit-characters/

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).

Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.

Example 1:

Input: 
bits = [1, 0, 0]
Output: True
Explanation: 
The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.

 

Example 2:

Input: 
bits = [1, 1, 1, 0]
Output: False
Explanation: 
The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.

 

Note:

  • 1 <= len(bits) <= 1000.
  • bits[i] is always 0 or 1

2. Solution:

class Solution:
def dfs(self, bits):
size = len(bits)

if size == 1:
return True

if size == 2:
if bits[0] == 1:
return False
else:
return True

if size >= 3:
if bits[0] == 1:
return self.dfs(bits[2:])
else:
return self.dfs(bits[1:])

def isOneBitCharacter(self, bits):
"""
:type bits: List[int]
:rtype: bool
"""
return self.dfs(bits)

转载于:https://www.cnblogs.com/ordili/p/9992179.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值