考虑无符号整数的二进制中1的个数

代码

        static int CountOneInInteger(int value)
        {
            int iter=1;
            int count=0;
            for(int i=0;i<32;i++)
            {
                if((value&iter)!=0)
                    count++;
                iter<<=1;
            }
            return count;
        }

 

转载于:https://www.cnblogs.com/qixue/archive/2010/02/08/1665881.html