POJ 3903 Stock Exchange LIS

本文介绍了一种解决最长递增子序列(LIS)问题的nlogn复杂度算法实现。通过使用动态规划结合二分查找的方法,有效地提高了求解效率。文章提供了完整的代码示例,并通过一个股票价格趋势分析的问题实例来展示该算法的应用。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

题目链接http://poj.org/problem?id=3903

题目大意:LIS的nlog(n)写法。

解题思路:dp[i]:=长度为i的最长递增子序列的末尾元素最小值。那么由于dp[i]形成了一个有序的序列,所以可以采用二分的办法。

dp[j] = a[i]   dp[j] <= a[j] < dp[j + 1]

代码:

 1 const int inf = 0x3f3f3f3f;
 2 const int maxn = 1e5 + 5;
 3 int a[maxn], n;
 4 int dp[maxn];
 5 
 6 void solve(){
 7     memset(dp, 0x3f, sizeof(dp));
 8     for(int i = 1; i <= n; i++){
 9         *lower_bound(dp + 1, dp + 1 + n, a[i]) = a[i];
10     }
11     int ans = lower_bound(dp + 1, dp + 1 + n, inf) - dp - 1;
12     printf("%d\n", ans);
13 }
14 int main(){
15     while(scanf("%d", &n) != EOF){
16         for(int i = 1; i <= n; i++) scanf("%d", &a[i]);
17         solve();
18     }
19 }

题目:

Stock Exchange
Time Limit: 1000MS Memory Limit: 65536K
Total Submissions: 7115 Accepted: 2474

Description

The world financial crisis is quite a subject. Some people are more relaxed while others are quite anxious. John is one of them. He is very concerned about the evolution of the stock exchange. He follows stock prices every day looking for rising trends. Given a sequence of numbers p1, p2,...,pn representing stock prices, a rising trend is a subsequence pi1 < pi2 < ... < pik, with i1 < i2 < ... < ik. John’s problem is to find very quickly the longest rising trend.

Input

Each data set in the file stands for a particular set of stock prices. A data set starts with the length L (L ≤ 100000) of the sequence of numbers, followed by the numbers (a number fits a long integer). 
White spaces can occur freely in the input. The input data are correct and terminate with an end of file.

Output

The program prints the length of the longest rising trend. 
For each set of data the program prints the result to the standard output from the beginning of a line.

Sample Input

6 
5 2 1 4 5 3 
3  
1 1 1 
4 
4 3 2 1

Sample Output

3 
1 
1

Hint

There are three data sets. In the first case, the length L of the sequence is 6. The sequence is 5, 2, 1, 4, 5, 3. The result for the data set is the length of the longest rising trend: 3.

转载于:https://www.cnblogs.com/bolderic/p/7367293.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值