HDU 3065 病毒侵袭持续中 AC自动机

HDU 3065

AC自动机 这个也可以拿来做模板了，使用静态数组模拟建树

  1 //#pragma comment(linker, "/STACK:1677721600")
  2 #include <map>
  3 #include <set>
  4 #include <stack>
  5 #include <queue>
  6 #include <cmath>
  7 #include <ctime>
  8 #include <vector>
  9 #include <cstdio>
 10 #include <cctype>
 11 #include <cstring>
 12 #include <cstdlib>
 13 #include <iostream>
 14 #include <algorithm>
 15 using namespace std;
 16 #define INF 0x3f3f3f3f
 17 #define inf (-((LL)1<<40))
 18 #define lson k<<1, L, (L + R)>>1
 19 #define rson k<<1|1,  ((L + R)>>1) + 1, R
 20 #define mem0(a) memset(a,0,sizeof(a))
 21 #define mem1(a) memset(a,-1,sizeof(a))
 22 #define mem(a, b) memset(a, b, sizeof(a))
 23 #define FIN freopen("in.txt", "r", stdin)
 24 #define FOUT freopen("out.txt", "w", stdout)
 25 #define rep(i, a, b) for(int i = a; i <= b; i ++)
 26 #define dec(i, a, b) for(int i = a; i >= b; i --)
 27 
 28 template<class T> T MAX(T a, T b) { return a > b ? a : b; }
 29 template<class T> T MIN(T a, T b) { return a < b ? a : b; }
 30 template<class T> T GCD(T a, T b) { return b ? GCD(b, a%b) : a; }
 31 template<class T> T LCM(T a, T b) { return a / GCD(a,b) * b;    }
 32 
 33 //typedef __int64 LL;
 34 typedef long long LL;
 35 const int MAXN = 1000 + 100;
 36 const int MAXM = 2000000 + 100;
 37 const double eps = 1e-8;
 38 LL MOD = 1000000007;
 39 
 40 
 41 const int SIGMA_SIZE = 27;
 42 const int MAX_LEN = 52;
 43 
 44 struct ACMachine {
 45     int ch[MAXN * MAX_LEN][SIGMA_SIZE];
 46     int val[MAXN * MAX_LEN];
 47     int fail[MAXN * MAX_LEN];
 48     int last[MAXN * MAX_LEN];
 49 
 50     int id[MAXN * MAX_LEN], ans[MAXN];
 51 
 52     int node_cnt;
 53     queue<int>q;
 54 
 55     void init() {
 56         node_cnt = 0;
 57         mem0(ch); mem0(val);
 58         mem0(fail); mem0(last);
 59         while(!q.empty()) q.pop();
 60     }
 61     int get_idx(char ch) {
 62         if(ch >= 'A' && ch <= 'Z')
 63             return ch - 'A';
 64         return 26;
 65     }
 66     void insert_to_tree(char *str, int p) {
 67         int u = 0, len = strlen(str);
 68         rep (i, 0, len - 1) {
 69             int c = get_idx(str[i]);
 70             if(!ch[u][c]) {
 71                 ch[u][c] = ++node_cnt;
 72             }
 73             u = ch[u][c];
 74         }
 75         val[u] ++;
 76 
 77         id[u] = p;
 78     }
 79     void get_fail() {
 80         rep (c, 0, SIGMA_SIZE - 1) {
 81             int u = ch[0][c];
 82             if(u) q.push(u);
 83         }
 84         while(!q.empty()) {
 85             int r = q.front(); q.pop();
 86             rep (c, 0, SIGMA_SIZE - 1) {
 87                 int u = ch[r][c];
 88                 if(!u) {
 89                     ch[r][c] = ch[fail[r]][c];
 90                     continue;
 91                 }
 92                 q.push(u);
 93                 int v = fail[r];
 94                 while(v && !ch[v][c]) v = fail[v];
 95                 fail[u] = ch[v][c];
 96                 last[u] = val[fail[u]] ? fail[u] : last[fail[u]];
 97             }
 98         }
 99     }
100     void find_ans(char *str) {
101 
102         mem0(ans);
103 
104         int len = strlen(str), u = 0;
105         rep(i, 0, len - 1) {
106             int c = get_idx(str[i]);
107             u = ch[u][c];
108             int v = u;
109             while(v) {
110                 if(val[v]) {
111                     ans[id[u]] ++;
112                 }
113                 v = last[v];
114             }
115         }
116 
117     }
118 }acm;
119 
120 int n;
121 char str[MAXM], s[MAXN][MAX_LEN];
122 
123 int main()
124 {
125 //    FIN;
126     while(~scanf("%d%*c", &n)) {
127         acm.init();
128         rep (i, 1, n) {
129             scanf("%s", s[i]);
130             acm.insert_to_tree(s[i], i);
131         }
132         acm.get_fail();
133         scanf("%s", str);
134         acm.find_ans(str);
135         rep (i, 1, n) if(acm.ans[i]){
136             printf("%s: %d\n", s[i], acm.ans[i]);
137         }
138     }
139     return 0;
140 }

 

转载于:https://www.cnblogs.com/gj-Acit/p/4678614.html