计算公历

最新推荐文章于 2023-11-14 18:35:07 发布

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最新推荐文章于 2023-11-14 18:35:07 发布

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CC 4.0 BY-SA版权

原文链接：http://www.cnblogs.com/liufang/p/3729358.html

void GregorianDay(struct rtc_time * tm)
{
int leapsToDate;
int lastYear;
int day;
int MonthOffset[] = { 0,31,59,90,120,151,181,212,243,273,304,334 };

lastYear=tm->tm_year-1;

/*计算从公元元年到计数的前一年之中一共经历了多少个闰年*/
leapsToDate = lastYear/4 - lastYear/100 + lastYear/400;

/*如若计数的这一年为闰年，且计数的月份在2月之后，则日数加1，否则不加1*/
if((tm->tm_year%4==0) &&
((tm->tm_year%100!=0) || (tm->tm_year%400==0)) &&
(tm->tm_mon>2)) {
/*
* We are past Feb. 29 in a leap year
*/
day=1;
} else {
day=0;
}

day += lastYear*365 + leapsToDate + MonthOffset[tm->tm_mon-1] + tm->tm_mday; /*计算从公元元年元旦到计数日期一共有多少天*/

tm->tm_wday=day%7;
}

转载于:https://www.cnblogs.com/liufang/p/3729358.html