uva - Broken Keyboard (a.k.a. Beiju Text)（链表）

　　　　　　　　　　　　　　

11988 - Broken Keyboard (a.k.a. Beiju Text)

You’re typing a long text with a broken keyboard. Well it’s not so badly broken. The only problem
with the keyboard is that sometimes the “home” key or the “end” key gets automatically pressed
(internally).
You’re not aware of this issue, since you’re focusing on the text and did not even turn on the
monitor! After you finished typing, you can see a text on the screen (if you turn on the monitor).
In Chinese, we can call it Beiju. Your task is to find the Beiju text.
Input
There are several test cases. Each test case is a single line containing at least one and at most 100,000
letters, underscores and two special characters ‘[’ and ‘]’. ‘[’ means the “Home” key is pressed
internally, and ‘]’ means the “End” key is pressed internally. The input is terminated by end-of-file
(EOF).
Output
For each case, print the Beiju text on the screen.
Sample Input
This_is_a_[Beiju]_text
[[]][][]Happy_Birthday_to_Tsinghua_University
Sample Output
BeijuThis_is_a__text
Happy_Birthday_to_Tsinghua_University

题解：

给定一个字符串，内部含有”【“和”】“光标转移指令，

【代表光标移向文章头，】代表光标移向文章尾，问最终在屏幕上显示的字符串序列是？

Cur代表当前光标的位置，en代表当前结束的位置。。。模拟输入就好了，用链表；

链表，好题，代码好吊，看了半天，越看越感觉吊；

 

代码：

#include<iostream>
#include<cstring>
#include<cmath>
#include<cstdio>
#include<algorithm>
using namespace std;
const int MAXN=1e5+100;
int en,cur,next[MAXN];
char s[MAXN];
int main(){
	while(~scanf("%s",s+1)){
		int len=strlen(s+1);
		cur=en=0;
		next[0]=0;
		for(int i=1;i<=len;i++){
			if(s[i]=='[')cur=0;
			else if(s[i]==']')cur=en;
			else{
				next[i]=next[cur];
				next[cur]=i;
				if(cur==en)en=i;
				cur=i;
			}
		}
		for(int i=next[0];i!=0;i=next[i])printf("%c",s[i]);
		puts("");
	}
	return 0;
}

　　

转载于:https://www.cnblogs.com/handsomecui/p/4984810.html