HDU 2131 Probability

本文介绍了一个基于C++的简单概率计算游戏实现。游戏中,用户给出一个字母和一个单词,程序计算并输出该字母在单词中出现的概率,精确到小数点后五位。代码使用了标准输入输出流,通过遍历字符串来计数指定字符的出现次数。

http://acm.hdu.edu.cn/showproblem.php?pid=2131

 

Problem Description
Mickey is interested in probability recently. One day , he played a game which is about probability with mini.First mickey gives a letter and a word to mini.Then mini calculate the probability that the letter appears in the word.For example,give you the letter "a" and the word "apple". the probability of this case is 0.20000.
 
Input
The input contains several test cases. Each test case consists of a letter and a word.The length of the word is no longer than 200.
 
Output
For each test case, print the probability rounded to five digits after the decimal point.
 
Sample Input
a apple
c Candy
a banana
 
Sample Output
0.20000
0.20000
0.50000
 
代码:
#include <bits/stdc++.h>
using namespace std;

const int maxn = 1e5 + 10;
char s[maxn];
char c;

int main() {
    while(~scanf("%c%s", &c, s)) {
        getchar();
        int len = strlen(s);
        int cnt = 0;
        for(int i = 0; i< len; i ++) {
            if(s[i] == c || s[i] == c - 32 || s[i] == c + 32)
                cnt ++;
        }
        printf("%.5lf\n", 1.0 * cnt / len);
    }
    return 0;
}

  

转载于:https://www.cnblogs.com/zlrrrr/p/9681537.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值