Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
,
return true.
Given "foo"
, "bar"
,
return false.
Given "paper"
, "title"
,
return true.
Note:
You may assume both s and t have the same length.
核心思想就是只要单词的每个字母是”一一映射“,就符合条件,每次如果没有映射关系,就建立单词a到单词b的相应位置的字母映射,如果已经存在这样的映射,就检查是否符合对应关系,即key value是否对应
public boolean isIsomorphic(String s, String t)
{
int slen=s.length();
int tlen=t.length();
if(slen!=tlen)
return false;
HashMap<Character, Character> hashmap=new HashMap<>();
for(int i=0;i<slen;i++)
{
char schar=s.charAt(i);
char tchar=t.charAt(i);
if(!hashmap.containsKey(schar)&&!hashmap.containsValue(tchar))
hashmap.put(schar, tchar);
else {
if(hashmap.get(schar)==null||hashmap.get(schar)!=tchar)
return false;
}
}
return true;
}