412. Fizz Buzz

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本文解析了经典的编程面试题FizzBuzz，并提供了一个简洁的Java实现方案。文章详细介绍了题目的要求，即对于1到n的数字，能被3整除的替换为Fizz，能被5整除的替换为Buzz，同时被3和5整除的替换为FizzBuzz。

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412. Fizz Buzz

Description Hints Submissions Solutions

Total Accepted: 68068
Total Submissions: 115613
Difficulty: Easy
Contributor: LeetCode

Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

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题意：

整除3和5的数输出 FizzBuzz，整除3的输出Fizz，整除5的输出Buzz

算法思路：

用if else结构依次判断即可，需要注意的是要把int类型转化为String类型的加入list里面

代码：

package easy;

import java.util.LinkedList;
import java.util.List;

public  class FizzBuzz {
	public static List<String> fizzBuzz(int n) {
		List<String> list = new LinkedList<String>();
        for(int i=1; i<=n; i++){
        	if(i%3==0 && i%5==0){
        		list.add("FizzBuzz");
        	}else if(i%3==0 && i%5!=0){
        		list.add("Fizz");
        	}else if(i%5==0 && i%3!=0){
        		list.add("Buzz");
        	}else{
        		list.add(String.valueOf(i));
        	}
        }
        
        return list;
    }

	public static void main(String[] args) {
		System.out.println(fizzBuzz(15));

	}

}