题目
Given a binary tree, return the preorder traversal of its nodes’ values.
For example:
Given binary tree {1,#,2,3},
return [1,2,3].
Note: Recursive solution is trivial, could you do it iteratively?
给定一颗二叉树,返回前序遍历结果。用循环实现而不是递归
代码
class Solution {
public:
vector<int> preorderTraversal(TreeNode *root) {
vector<int> res;
if(!root)
return res;
stack<TreeNode*> ss;
ss.push(root);
while(!ss.empty()) {
TreeNode *t = ss.top();
ss.pop();
res.push_back(t->val);
if(t->right)
ss.push(t->right);
if(t->left)
ss.push(t->left);
}
return res;
}
};