LUA:根据上排给出的十个数，在其下排填出对应的十个数，要求下排每个数都是先前上排那十个数在下排出现的次数

#LUA:根据上排给出的十个数，在其下排填出对应的十个数，要求下排每个数都是先前上排那十个数在下排出现的次数，0 1 2 3 4 5 6 7 8 9

local top = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
local bottom = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0}
local len = #top

function getCount(num, table)
    if not table then
        return 0 
    end
    
    local count = 0
    for i = 1, #table do
        if table[i] == num then
            count = count + 1 
        end
    end

    return count 
end

local endFlag = false
while(not endFlag) do
    endFlag = true
    for i = 1, len do
        local count = getCount(i - 1, bottom);  
        if bottom[i] ~= count then
            bottom[i] = count
            endFlag = false
        end
    end
end

for i=1,10 do
    print(i- 1, bottom[i])
end

结果

原始数列：0 1 2 3 4 5 6 7 8 9
出现次数：6 2 1 0 0 0 1 0 0 0