Python实例 -- 收发邮件

Python实例 -- 收发邮件 2012-09-12 20:17:49

分类： LINUX

python发邮件

1. #!/usr/bin/env python3
   
2. #coding: utf-8
   
3. import smtplib
   
4. from email.mime.text import MIMEText
   
5. from email.header import Header
   
6.   
   
7. sender = '***'
   
8. receiver = '***'
   
9. subject = 'python email test'
   
10. smtpserver = 'smtp.163.com'
    
11. username = '***'
    
12. password = '***'
    
13.   
    
14. msg = MIMEText('你好','plain','utf-8')#中文需参数‘utf-8’，单字节字符不需要
    
15. msg['Subject'] = Header(subject, 'utf-8')
    
16.   
    
17. smtp = smtplib.SMTP()
    
18. smtp.connect('smtp.163.com')
    
19. smtp.login(username, password)
    
20. smtp.sendmail(sender, receiver, msg.as_string())
    
21. smtp.quit()

python收邮件

1. #!/usr/bin/env python3 
2. # -*- coding: utf-8 -*-
   
3.       
   
4.     import poplib
   
5.     from email import parser
   
6.       
   
7.     host = 'pop.gmail.com'
   
8.     username = 'mine@gmail.com'
   
9.     password = '*******'
   
10.       
    
11.     pop_conn = poplib.POP3_SSL(host)
    
12.     pop_conn.user(username)
    
13.     pop_conn.pass_(password)
    
14.       
    
15.     #Get messages from server:
    
16.     messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
    
17.       
    
18.     # Concat message pieces:
    
19.     messages = ["\n".join(mssg[1]) for mssg in messages]
    
20.       
    
21.     #Parse message intom an email object:
    
22.     messages = [parser.Parser().parsestr(mssg) for mssg in messages]
    
23.     for message in messages:
    
24.         print message['Subject']
    
25.     pop_conn.quit()