LeetCode每日一题(2087. Minimum Cost Homecoming of a Robot in a Grid)

最新推荐文章于 2023-03-21 20:01:42 发布

原创

最新推荐文章于 2023-03-21 20:01:42 发布 · 297 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#leetcode #算法

给定一个机器人初始位置和目标位置，以及行和列的成本数组，计算机器人返回原点的最小总成本。问题的关键在于理解每条最短路径的消耗是相同的，因为消耗仅与进入特定行或列有关，而与当前列或行无关。

There is an m x n grid, where (0, 0) is the top-left cell and (m - 1, n - 1) is the bottom-right cell. You are given an integer array startPos where startPos = [startrow, startcol] indicates that initially, a robot is at the cell (startrow, startcol). You are also given an integer array homePos where homePos = [homerow, homecol] indicates that its home is at the cell (homerow, homecol).

The robot needs to go to its home. It can move one cell in four directions: left, right, up, or down, and it can not move outside the boundary. Every move incurs some cost. You are further given two 0-indexed integer arrays: rowCosts of length m and colCosts of length n.

If the robot moves up or down into a cell whose row is r, then this move costs rowCosts[r].
If the robot moves left or right into a cell whose column is c, then this move costs colCosts[c].
Return the minimum total cost for this robot to return home.

Example 1:

Input: startPos = [1, 0], homePos = [2, 3], rowCosts = [5, 4, 3], colCosts = [8, 2, 6, 7]
Output: 18

Explanation: One optimal path is that:
Starting from (1, 0)
-> It goes down to (2, 0). This move costs rowCosts[2] = 3.
-> It goes right to (2, 1). This move costs colCosts[1] = 2.
-> It goes right to (2, 2). This move costs colCosts[2] = 6.
-> It goes right to (2, 3). This move costs colCosts[3] = 7.
The total cost is 3 + 2 + 6

最低0.47元/天解锁文章