Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
The number of elements initialized in nums1and nums2 are m and n respectively.
class Solution {
public:
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
int index1 = m - 1;
int index2 = n - 1;
int index = m + n - 1;
while(index1>=0 && index2 >= 0){
if(nums1[index1]>nums2[index2]){
nums1[index] = nums1[index1];
index--;
index1--;
}else{
nums1[index] = nums2[index2];
index--;
index2--;
}
}
while(index1>=0){
nums1[index] = nums1[index1];
index--;
index1--;
}
while(index2>=0){
nums1[index] = nums2[index2];
index--;
index2--;
}
}
};