2022.12.8---类中的继承

代码实现

        定义一个学生类（student）：保护成员---姓名、年龄、成绩及相关函数

        定义一个老师类（teacher）：保护成员---年龄、职称及相关函数

        由学生类和老师类共同派生出研究生类（graduate）：成员---性别

实例化出研究生类的对象，并输出该对象的所有信息；

#include <iostream>

using namespace std;

class student
{
protected:
    string name;
    int age;
    double score;
public:
    student() {}        //无参构造
    student(string n,int a,double s):name(n),age(a),score(s){}  //有参构造
    ~student(){}        //析构函数
    void show()
    {
        cout<<"student name :"<<name<<endl;
        cout<<"student age :"<<age<<endl;
        cout<<"student score :"<<score<<endl;
    }
};

class teacher
{
protected:
    int age;
    string subject;
public:
    teacher() {}        //无参构造
    teacher(int a,string s):age(a),subject(s){}     //有参构造
    ~teacher(){}        //析构函数
    void show()
    {
        cout<<"teacher age: "<<age<<endl;
        cout<<"teacher subject: "<<subject<<endl;
    }
};

class graduate:public student,public teacher    //研究生类继承于学生类和老师类
{
public:
    string sex;
    graduate(){}        //无参构造
    graduate(string stu_n,int stu_a,double stu_s,int tea_a,string tea_s,string s):
        student(stu_n,stu_a,stu_s),teacher(tea_a,tea_s),sex(s){}    //有参构造
    ~graduate(){}       //析构函数
    void show()
    {
        cout<<"graduate name: "<<name<<endl;
        cout<<"graduate age: "<<student::age<<endl;     //访问继承来的同名成员要指定父类名
        cout<<"graduate score: "<<score<<endl;
        cout<<"graduate subject: "<<subject<<endl;
        cout<<"graduate sex: "<<sex<<endl;
    }

};

int main()
{
    graduate g("wang",19,77,37,"math","boy");   //调用研究生类的有参构造
    g.show();
    return 0;
}