题目
The cows are thrilled because they’ve just learned about encrypting messages. They think they will be able to use secret messages to plot meetings with cows on other farms.
Cows are not known for their intelligence. Their encryption method is nothing like DES or BlowFish or any of those really good secret coding methods. No, they are using a simple substitution cipher.
The cows have a decryption key and a secret message. Help them decode it. The key looks like this:
yrwhsoujgcxqbativndfezmlpk
Which means that an ‘a’ in the secret message really means ‘y’; a ‘b’ in the secret message really means ‘r’; a ‘c’ decrypts to ‘w’; and so on. Blanks are not encrypted; they are simply kept in place.
(这句是解题关键)
Input text is in upper or lower case, both decrypt using the same decryption key, keeping the appropriate case, of course.
Input
-
Line 1: 26 lower case characters representing the decryption key
-
Line 2: As many as 80 characters that are the message to be decoded
Output -
Line 1: A single line that is the decoded message. It should have the same length as the second line of input.
Sample Input
eydbkmiqugjxlvtzpnwohracsf //加密后的26个字母
Kifq oua zarxa suar bti yaagrj fa xtfgrj //加密后的文本
Sample Output
Jump the fence when you seeing me coming
这居然也是个多组输入输出
这题主要就是注意一下大小写字母,大小写字母ASCII码值差32
#include <stdio.h>
#include <string.h>
int main()
{
char a[30];
while(scanf("%s",a)!=EOF)
{
getchar(); //记得吸收回车符
char b[180];
gets(b);
int len=strlen(b);
for(int i=0;i<len;i++)
{
if(b[i]==' ') printf(" ");
else if(b[i]>='a'&&b[i]<='z') printf("%c",a[b[i]-'a']);
else if(b[i]>='A'&&b[i]<='Z') printf("%c",a[b[i]-'A']-32);
}
printf("\n");
}
return 0;
}
本文介绍了一种简单的替换加密方法,通过使用特定的解密密钥来解读加密后的消息。示例展示了如何使用C语言编写解密程序,处理大小写字母并保持适当的大小写。代码实现了读取加密密钥和加密消息,然后根据密钥进行解密。
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