原sql
-- 结果为 200
SELECT COUNT(id) FROM a WHERE order_flow = 1 AND order_status = 1 AND deleted = 0
-- 结果为 180
SELECT COUNT(id) FROM b WHERE state = 0 AND deleted =0
左连接查询结果为0,需求为找到这相差的20条数据
写法1
-- 结果为0条
SELECT o.* from
a o
left join
b c
on o.enterprise_id=c.id
where o.order_status=1 and o.deleted=0 and c.deleted=0 and c.state = 0
and c.id is null;
写法2(结果正确)
-- 结果有20条
SELECT o.* from a o
left join (SELECT id FROM b WHERE state = 0 AND deleted =0) c on o.enterprise_id=c.id
where o.order_flow=1 and o.order_status=1 and o.deleted=0
and c.id is null;
原因为写法1中 c.deleted=0 and c.state = 0 对连接数据结果造成了影响
所以应该首先把连接的表做出来后在连接