1480. 一维数组的动态和
来源:力扣(LeetCode)
链接: https://leetcode.cn/problems/running-sum-of-1d-array/description/
给你一个数组 nums
。数组「动态和」的计算公式为:
r u n n i n g S u m [ i ] = s u m ( n u m s [ 0 ] … n u m s [ i ] ) runningSum[i] = sum(nums[0]…nums[i]) runnin
来源:力扣(LeetCode)
链接: https://leetcode.cn/problems/running-sum-of-1d-array/description/
给你一个数组 nums
。数组「动态和」的计算公式为:
r u n n i n g S u m [ i ] = s u m ( n u m s [ 0 ] … n u m s [ i ] ) runningSum[i] = sum(nums[0]…nums[i]) runnin