目录
1.题目
给你一个单链表的头节点 head
,请你判断该链表是否为回文链表。如果是,返回 true
;否则,返回 false
。
示例 1:
输入:head = [1,2,2,1] 输出:true
示例 2:
输入:head = [1,2] 输出:false
提示:
- 链表中节点数目在范围
[1, 105]
内 0 <= Node.val <= 9
2.C++代码
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* reverse(ListNode* head)
{
ListNode* cur = head;
ListNode* pre = NULL;
while(cur!=NULL)
{
ListNode* tmp = cur->next;
cur->next = pre;
pre = cur;
cur = tmp;
}
return pre;
}
bool isPalindrome(ListNode* head) {
ListNode *fast = head;
ListNode *slow = head;
while(fast->next!=NULL&&fast->next->next!=NULL)
{
slow = slow->next;
fast = fast->next->next;
}
ListNode *p1 = head;
ListNode *rev = reverse(slow->next);
//slow->next = NULL;
while(rev!=NULL)
{
if(p1->val != rev->val)
{
return false;
}
p1 = p1->next;
rev = rev->next;
}
return true;
}
};