Valid Sudoku

Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

The Sudoku board could be partially filled, where empty cells are filled with the character '.'.

A partially filled sudoku which is valid.

Note:
A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.

#include<stdio.h>
int isValidArray(char arr[]){
    int i,j,n;
    int arr1[9]={0};
    for(i=0;i<9;i++) printf("d:%c",arr[i]);
    printf("\n");
    for(i=0;i<9;i++){
        if(arr[i]=='.') continue;
        n=(arr[i]-'0')%9;
        arr1[n]++;
        if(arr1[n]>1) { printf("n=%d",n);return 0;}
        
    }
    return 1;

}

int isValidSudoku(char board[9][9]) {
    int i,j,k,l;
    int res=0;
    char arr[9]={'0'};
    char arr1[9]={'0'};
    for(i=0;i<9;i++){
        for(j=0;j<9;j++){
            arr[j]=board[i][j];
            arr1[j]=board[j][i];
        }
        if(isValidArray(arr)==0) return 0;
        if(isValidArray(arr1)==0) return 0;
    }
    for(l=0;l<3;l++){
        for(k=0;k<3;k++){
            for(i=l*3;i<l*3+3;i++){
                for(j=k*3;j<k*3+3;j++){ 
                    printf("w%c",board[i][j]);
                    arr[(i*3+j)%9]=board[i][j];
                }
            }
            if(isValidArray(arr)==0) return 0;
        }
    }
    return 1;
}

void main(){
    char array[9][9]={"53..7....","6..195...",".98....6.","8...6...3","4..8.3..1","7...2...6",".6....28.","...419..5","....8..79"};
    int res=isValidSudoku(array);
    printf("%d\n",res);

}