array地址问题(为何指向赋值，仍然地址不同）

最新推荐文章于 2022-11-08 14:14:24 发布

骑猪赛马

最新推荐文章于 2022-11-08 14:14:24 发布

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本文链接：https://blog.youkuaiyun.com/u014645119/article/details/50402213

这篇博客探讨了C++中array类型的赋值操作导致的地址不同的现象。通过示例代码展示了数组a1、a2、a3和a4的元素及地址，指出尽管a4等于a3，但它们的内存地址不同。博主推测这可能是因为C++对array进行了重载操作，赋值时并非简单地复制指针，而是进行了值的拷贝，因此即使内容相同，地址也会发生变化。

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代码quote：c++ primer plus ---- example 4.24

#include <iostream>
#include <vector>
#include <array>

int main(int argc, const char * argv[]) {
// insert code here...

using namespace std;

double a1[4] = {1.2, 2.4, 3.6, 4.8};
vector<double> a2(4);
a2[0] = 1.0/3.0;
a2[1] = 1.0/5.0;
a2[2] = 1.0/7.0;
a2[3] = 1.0/9.0;

array<double, 4> a3 = {3.14, 2.72, 1.62, 1.41};
array<double, 4> a4;
a4 = a3;

cout << "a1[2]: " << a1[2] << " at " << &a1[2] << endl;
cout << "a2[2]: " << a2[2] << " at " << &a2[2] << endl;
cout << "a3[2]: " << a3[2] << " at " << &a3[2] << endl;
cout << "a4[2]: " << a4[2] << " at " << &a4[2] << endl;

a1[-2] = 20.2;
cout << " a1[-2]: " << a1[-2] << " at " << &a1[-2] << endl;
cout << " a3[2]: " << a3[2] << " at " << &a3[2] << endl;
cout << " a4[2]: " << a4[2] << " at " << &a4[2] << endl;

return 0;
}