通过前序遍历和中序遍历构建二叉树
用中序遍历的根节点和第一个左节点获取做节点长度,右节点下标。
通过前序遍历(第一个节点)和后续遍历(最后一个节点)得到根节点
public class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) {
val = x;
}
}
/**
* 通过前序遍历和中序遍历构建二叉树,前提树节点值不重复
*
* @param pre 前序遍历的结果
* @param preRootNodeStart 前序遍历开始根节点下标
* @param preEnd 前序遍历集合最后一个下标
* @param inLeftNodeStart 中序遍历第一个左节点下标
* @param inPos 中序遍历值与下标映射关系
* @return
*/
private TreeNode buildTree(int[] pre, int preRootNodeStart, int preEnd, int inLeftNodeStart, Map<Integer, Integer> inPos) {
if (preRootNodeStart > preEnd) return null;
TreeNode root = new TreeNode(pre[preRootNodeStart]);
// 获取根节点在中序遍历的下标
int rootIdx = inPos.get(pre[preRootNodeStart]);
// 获取左子树的长度
int leftLen = rootIdx - inLeftNodeStart;
root.left = buildTree(pre, preRootNodeStart + 1, preRootNodeStart + leftLen, inLeftNodeStart, inPos);
root.right = buildTree(pre, preRootNodeStart + leftLen + 1, preEnd, rootIdx + 1, inPos);
return root;
}
public TreeNode buildTree(int[] pre, int[] in) {
Map<Integer, Integer> inPos = new HashMap<>();
for (int i = 0; i < in.length; i++) {
inPos.put(in[i], i);
}
return buildTree(pre, 0, pre.length - 1, 0, inPos);
}
private TreeNode buildTreePrePostArray(int[] post, int postStart, int postEnd, int inStart, Map<Integer, Integer> inPos) {
if (postStart > postEnd) return null;
TreeNode root = new TreeNode(post[postEnd]);
int rootIdx = inPos.get(post[postEnd]);
int leftLen = rootIdx - inStart;
root.left = buildTreePrePostArray(post, postStart, postStart + leftLen - 1, inStart, inPos);
root.right = buildTreePrePostArray(post, postStart +leftLen, postEnd - 1, rootIdx + 1, inPos);
return root;
}
// Time: O(n). Space:O(n)
public TreeNode buildTreePrePostArray(int[] in, int[] post) {
Map<Integer, Integer> inPos = new HashMap<>();
for (int i = 0; i < in.length; i++) {
inPos.put(in[i], i);
}
return buildTreePrePostArray(post, 0, post.length - 1, 0, inPos);
}