Problem A
Hashmat the brave warrior
Input: standard input
Output: standard output
Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.
Input
The input contains two integer numbers in every line. These two numbers in each line denotes the number of soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2^32. Input is terminated by End of File.
Output
For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in seperate line.
Sample Input:
10 1210 14
100 200
Sample Output:
24
100
Shahriar Manzoor
16-12-2000
#include <iostream>
using namespace std;
int main()
{
long long a,b;
while(cin>>a>>b)
{
cout<<(a<b ? b-a :a-b )<<endl;
}
return 0;
}
结果:
| # | Problem | Verdict | Language | Run Time | Submission Date | |
| 13376382 | 10055 | Hashmat the Brave Warrior | Accepted | C++ | 0.448 | 2014-03-23 14:46:57 |
本文介绍了一个简单的编程挑战,名为“Hashmat the Brave Warrior”。在这个问题中,Hashmat和他的士兵们面对对手前会计算双方士兵数量的差异来决定是否进行战斗。文章提供了输入输出样例以及一个用C++实现的解决方案。
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