uva Hangman Judge

本文介绍了一个简单的Hangman游戏胜负判断程序。该程序通过输入谜底及玩家猜测的字母序列来判断游戏结果,包括胜、负或放弃。文章提供了一个C++实现案例,并解释了程序如何根据游戏规则进行胜负判断。

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题目如下:

Hangman Judge 

In ``Hangman Judge,'' you are to write a program that judges a series of Hangman games. For each game, the answer to the

puzzle is given as well as the guesses. Rules are the same as the classic game of hangman, and are given as follows:
1. The contestant tries to solve to puzzle by guessing one letter at a time.
2. Every time a guess is correct, all the characters in the word that match the guess will be ``turned over.'' For example,

if your guess is ``o'' and the word is ``book'', then both ``o''s in the solution will be counted as ``solved.''
3. Every time a wrong guess is made, a stroke will be added to the drawing of a hangman, which needs 7 strokes to complete.

Each unique wrong guess only counts against the contestant once.

   ______  
   |  |    
   |  O    
   | /|\   
   |  |    
   | / \   
 __|_      
 |   |______
 |_________|

4. If the drawing of the hangman is completed before the contestant has successfully guessed all the characters of the

word, the contestant loses.
5. If the contestant has guessed all the characters of the word before the drawing is complete, the contestant wins the

game.
6. If the contestant does not guess enough letters to either win or lose, the contestant chickens out.

Your task as the ``Hangman Judge'' is to determine, for each game, whether the contestant wins, loses, or fails to finish a

game.

 

Input

Your program will be given a series of inputs regarding the status of a game. All input will be in lower case. The first

line of each section will contain a number to indicate which round of the game is being played; the next line will be the

solution to the puzzle; the last line is a sequence of the guesses made by the contestant. A round number of -1 would

indicate the end of all games (and input).

 

Output

The output of your program is to indicate which round of the game the contestant is currently playing as well as the result

of the game. There are three possible results:


You win.
You lose.
You chickened out.

 

Sample Input


1
cheese
chese
2
cheese
abcdefg
3
cheese
abcdefgij
-1

 

Sample Output


Round 1
You win.
Round 2
You chickened out.
Round 3
You lose.

 

 

简单题,AC的代码如下:

#include
#include
#include
using namespace std;
int main()
{int n,len1,len2,i,j,ok=0,no=0,you=0;
cin>>n;
getchar();
while(n!=-1)
{no=0;
char s1[50],s2[30];
cin>>s1>>s2;
len1=strlen(s1);
len2=strlen(s2);
for(i=0;i<=len2-1;i++)
{ok=0;
you=0;
for(j=0;j<=len1-1;j++)
{if(s2[i]==s1[j])
{s1[j]='*';
ok=1;}
}
if(ok==0)
no++;
for(j=0;j<=len1-1;j++)
if(s1[j]!='*')
you=1;
if(no>=7)
{cout<<"Round "<>n;
getchar();
}
return 0;
}

 

 

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