102. Binary Tree Level Order Traversal | 层序遍历
class Solution {
public List<List<Integer>> levelOrder(TreeNode root) {
List<List<Integer>> res = new LinkedList<>();
if(root==null) return res;
Queue<TreeNode> q = new LinkedList<>();
q.offer(root);
while(!q.isEmpty()) {
int level = q.size();
List<Integer> list = new LinkedList<>();
for(int i=0; i<level; i++) {
TreeNode node = q.poll();
list.add(node.val);
if(node.left!=null) q.offer(node.left);
if(node.right!=null) q.offer(node.right);
}
res.add(list);
}
return res;
}
}