题目连接:http://acm.hdu.edu.cn/diy/contest_showproblem.php?cid=23144&pid=1001
简单的并查集题目,先做一次并查集,然后如果f[x] == x那么联通分量数目加1
代码如下:
#include<iostream>
#include<algorithm>
#include<string>
#include<stack>
#include<queue>
#include<set>
#include<map>
#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
#include<time.h>
#include<math.h>
#define N 1005
#define eps 1e-9
#define pi acos(-1.0)
#define P system("pause")
using namespace std;
int f[N];
int find(int x)
{
return x == f[x] ? x : f[x] = find(f[x]);
}
int main()
{
//freopen("input.txt","r",stdin);
//freopen("output.txt","w",stdout);
int n,m;
while(scanf("%d",&n) && n)
{
scanf("%d",&m);
int i;
int x,y;
for(i = 0; i <= n; i++)
f[i] = i;
for(i = 0; i < m; i++)
{
scanf("%d%d",&x,&y);
x = find(x);
y = find(y);
if(x != y) f[x] = y;
}
int ans = 0;
for(i = 1; i <= n; i++)
// {cout<<f[i]<<" ";
if(f[i] == i)
ans++;
//}cout<<endl;
printf("%d\n",ans-1);
}
// P;
return 0;
}