Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
Example:
MyStack stack = new MyStack();
stack.push(1);
stack.push(2);
stack.top(); // returns 2
stack.pop(); // returns 2
stack.empty(); // returns false
Notes:
- You must use only standard operations of a queue -- which means only
push to back
,peek/pop from front
,size
, andis empty
operations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
思路:用一个queue来循环就可以了。
class MyStack {
private Queue<Integer> queue;
/** Initialize your data structure here. */
public MyStack() {
queue = new LinkedList<Integer>();
}
/** Push element x onto stack. */
public void push(int x) {
queue.add(x);
}
/** Removes the element on top of the stack and returns that element. */
public int pop() {
int size = queue.size();
int count = 0;
while(count < size - 1) {
queue.add(queue.poll());
count++;
}
return queue.poll();
}
/** Get the top element. */
public int top() {
int size = queue.size();
int count = 0;
while(count < size - 1) {
queue.add(queue.poll());
count++;
}
// 选出来之后,再加入尾巴;
int last = queue.poll();
queue.offer(last);
return last;
}
/** Returns whether the stack is empty. */
public boolean empty() {
return queue.size() == 0;
}
}
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* boolean param_4 = obj.empty();
*/