Two Sum

 

Given an arrayof integers, find two numbers such that they add up to a specific targetnumber.

The functiontwoSum should return indices of the two numbers such that they add up to thetarget, where index1 must be less than index2. Please note that your returnedanswers (both index1 and index2) are not zero-based.

You may assumethat each input would have exactly one solution.

Input: numbers={2, 7, 11, 15}, target=9

Output: index1=1, index2=2

class Solution {
public:
    void keepSort(vector<int> &array,vector<int>&src,int pos,int size ){
        int n = size;
        int left = 2*pos+1;
        int right = 2*pos+2;
        int min = pos;
        if ( pos<=n/2 ){
            if (  left <n && src[array[min]] < src[array[left]]  ){
                min = left;
            }
            if ( right<n && src[array[min]] < src[array[right]] ){
                min = right;
            }
            
            if ( min!=pos ){
                swap(array[min],array[pos]);
                keepSort(array,src,min,size);
            }   
        }
    }
    void buildHeap(vector<int> &array,vector<int> &src){
        int size = array.size();
        for ( int i=size/2; i>=0; --i ){
            keepSort(array,src,i,size);
        }
    }
    void heapSort(vector<int> &numbers,vector<int> &src){
        buildHeap(numbers,src);
        
        int size = numbers.size();
        while ( --size ){
            swap(numbers[0],numbers[size]);
            keepSort(numbers,src,0,size);
        }
    }
    vector<int> twoSum(vector<int> &numbers, int target) {
        vector<int> array;
        vector<int> pos;
        int n = numbers.size();
        for ( int i=0; i<n ; ++i ){
            pos.push_back(i);
        }
        heapSort(pos,numbers);
        int i=0,j=numbers.size()-1;
        while ( i<j ){
            if ( numbers[pos[i]]+numbers[pos[j]]==target ){
                if (pos[i]>pos[j]){
                    swap(pos[i],pos[j]);
                }
                array.push_back(pos[i]+1);
                array.push_back(pos[j]+1);
                break;
            } else if(numbers[pos[i]]+numbers[pos[j]]<target) {
                ++i;   
            } else{
                --j;
            } 
        }
        return array;
    }

};


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值