转载请注明出处:z_zhaojun的博客
原文地址
题目地址
Binary Tree Preorder Traversal
Given a binary tree, return the preorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3},
return [1,2,3].
思路:优先添加遍历左子树,在遍历的同时判断当前节点的右子树是否为空,如果不为空则添加到nodeList(类似栈,实现先进后出,最晚add的最先remove)中,当左子树遍历完毕后,再通过nodeList进行右子树的遍历。
实现代码(Java):
public class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> valList = new ArrayList<>();
List<TreeNode> nodeList = new ArrayList<>();
while (root != null) {
valList.add(root.val);
if (root.right != null) {
nodeList.add(root.right);
}
if (root.left != null) {
root = root.left;
} else {
if (nodeList.size() > 0) {
root = nodeList.get(nodeList.size() - 1);
nodeList.remove(nodeList.size() - 1);
} else {
break;
}
}
}
return valList;
}
}