Write a SQL query to find all duplicate emails in a table named Person.
+----+---------+
| Id | Email |
+----+---------+
| 1 | a@b.com |
| 2 | c@d.com |
| 3 | a@b.com |
+----+---------+
For example, your query should return the following for the above table:
+---------+
| Email |
+---------+
| a@b.com |
+---------+
解题:按照Email分组,然后找出id出现次数超过1的Email。
SQL语句使用group by 和 having 实现:
select Email from Person group by Email having count(id) > 1;