码代码的猿猿

Problem Statement  TopCoder admin mystic_tc is sitting in front of a table. He found N sealed boxes of candies on the table.He is not sure how many candies each box contains. However, he

优先队列构造前两列....Backup PlanTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 775    Accepted Submission(s): 365Special JudgeProblem

A. Bitstime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputLet's denote as  the number of bits set ('1' bits)

Codeforces Round #277.5 (Div. 2)A. SwapSorttime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard output

贪心枚举,代码里的注释很详细C. Sums of Digitstime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputVasya had

每一步都取当前稳定的格子里面数字最大或者最小的数.用一个set维护当前可取的格子 *begin 最大  *(--end) 最小每删除一个格子都要对这个格子周围的6个格子进行稳定性检查一个格子上面的3个格子确定了这个格子的稳定性D. Cubestime limit per test3 secondsmemory limit pe

贪心的选择单调的序列进行划分dp处理拐点(gd)应该分到左边的单调序列还是右边的单调序列大量读入加输入挂D. Kindergartentime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputou

最远曼哈顿距离有两个性质:1: 对每个点(x,y)  分别计算  +x+y , -x+y , x-y , -x-y 然后统计每种组合的最大值就可以了, 不会对结果产生影响2: 去掉绝对值 , 设正号为0负号为1 则 两个点的符号是可以通过异或的得到的. 如两个点 P(x,y) 和 Q(a,b) 若去掉绝对值符号后P的两个坐标为 -x +y 既对应数字 10  那么Q对应的数字则为 01

将歌曲按低音从小到大排序,歌手也按低音从小到大排序.对每首歌曲,在一个SET中查找低音满足条件的而高音刚好满足条件的歌手E. Distributing Partstime limit per test2 secondsmemory limit per test256 megabytesinputstandard i

点转换成线段,然后简单贪心.....CF里神奇的贪心比较多.....D. Clique Problemtime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outpu

很有意思的贪心:Let's reformulate the condition in terms of a certain height the towers, which will be on the stairs. Then an appropriate amount of money of a person in the queue is equal to the hei

BFS沿着0走,记录下最靠近终点的1然后斜着扫描Walk OutTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2573    Accepted Submission(s): 506Problem D

贪心，能凑成一组就算一组Unrhymable RhymesTime Limit: 10 Seconds      Memory Limit: 32768 KB      Special JudgeAn amateur poet Willy is going to write his first abstract poem. Since abstract art

贪心：保存连续的n-k个数，求最小的一段方差。。。。预处理O1算期望。。。GalaxyTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 752    Accepted Submission(s): 176

贪心。。。。Two PipelinesTime Limit: 2 Seconds      Memory Limit: 65536 KB      Special JudgeThere are two oil pipelines going through Flatland. Each pipeline can be considered as a line on

枚举a分成多少段，让a的部分尽量大，b的部分尽量小A. Cardstime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputUser ainta

从两头开始取+在中位数上建巡逻站E. Police Patroltime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputImagine tha

递归，分治。。。C. Painting Fencetime limit per test1 secondmemory limit per test512 megabytesinputstandard inputoutputstandard outputBizon the Champion

简单贪心....B. Pasha Maximizestime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputPasha has a posit

ZCC Loves CodefiresTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 198    Accepted Submission(s): 105Problem DescriptionThough Z

所有满足的情况的属性和是一定的,而且属性和等于sum/2时得到的结果最大.CloneTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 574    Accepted Submission(s): 277

用一个栈维护b的值，每次把一个数放到栈顶。看栈首的值是不是大于这个数，如果大于的话将栈顶2个元素合并，b的值就是这两个栈顶元素的平均值。。。Room and MoorTime Limit: 12000/6000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s):

Parenthese sequenceTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 716    Accepted Submission(s): 335Problem Descriptionbobo f

FrogTime Limit: 3000/1500 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 634    Accepted Submission(s): 152Problem DescriptionOnce upon a time, the

贪心A. Partial Teachertime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputA teacher decides to gi

按x和y排序后,贪心从y大的覆盖 用mulitset维护下即可….Alice and BobTime Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3817 Accepted Submission(s): 1198Problem Des