ACM-a letter and a number

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

代码：

#include<iostream>
 using namespace std;
 int main()
 { int k,j;
 char i;
 cin>>k;
 while(k--)
 { cin>>i>>j;
 if(i<='Z'&&i>='A')
 cout<<i+j-64<<endl; 
 else if(i<='z'&&i>='a')
 cout<<96-i+j<<endl;
 } 
 }